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Solving word problems math

The solving word problems are can be expressed in algebraic or equation format. The word problems can be specified in simple form. Here also algebra concept is helped to do the solving word math problems. Algebra is the important part in mathematics which is used to find unknown variables by using the known variable. Let we see about the word problems solving in math.

Solved word problems in math

Example 1 for solving word problems in math :
Robin has 12 computers and Johnson has 8 computers .Determine the amount of computers did both of them have?

Solution:

Let Y = Total number of computers

The amount of 12 shirts and 8 is relevant to the computers. Let we denote the integers as the equation.

Y = 12 + 8

Let Y be the total amount of computers

Y = 20

So, totally 20 computers are there.

Example 2 for solving word problems in math :
The Airplane starts from Berlin at 7 P.M. and reaches Languisher at 9.25 A.M. The distance between the two places is 160km. If the time of stoppages is 25 min, find the ...
... speed of the Airplane

Solution: Distance = 160 Km

No. of hours between 7 P.M. and 9.25 A.M.

= 2 hrs 25 min

Time of stoppage = 25 min

Time Taken = 2 hrs 25 min – 25 min

= 2 hrs

Distance
Speed= ___________
Time

160
= ______
2
= 80 Km/ hr.

More problems in solving word problems of math

Example 1 for solving word problems in math :
Maria has 55 balls and 50 Venus. How many balls does she have?

Solution:

Let Z= Total number of cars
The sum of 55 cars and 50 Venus is equal to the total number of balls . It translates the problem into an equation.
Z = 55 + 50

Solve this equation.
Let Z = Total number of balls

P = 105

There are 105 total numbers of balls

Example 2 for solving word problems in math
The normal of a list of 40 numbers is 20. If we throw out one of the numbers, the normal of the remaining numbers is 8. What is the number that was removed?

Solution:

Step 1: The throw out the number could be obtained by difference between the sum of original 40 numbers and the sum of remaining 25 numbers i.e.

Sum of original 40 numbers – sum of remaining 25 numbers

Step 2: Using the formula

Sum of terms = Average* Number of terms

Sum of original 40 numbers = 20 × 40 = 800

Sum of remaining 8 numbers =8 × 40 = 320

Step 3: Using the formula from step 1

Number removed = sum of original 40 numbers – sum of remaining 8 numbers

800 – 320 = 480
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