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Cuboid

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By Author: nandan nayak
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A cuboid is a three dimensional object, that has 6 rectangular faces, 12 edges and 8 corners. A box, a book, a cupboard or a room are all examples of a cuboid. The pair of opposite faces of a cuboid are equal in size. The size or dimensions of a cuboid are usually described in terms of its length, width and height or length, depth and height, depending on the object under consideration. For example a cuboidal room would have length, width and height, where as a cuboidal cupboard would have length, depth and height.

Surface area of a cuboid

The surface area of a cuboid, is the sum of the areas of each of the 6 faces. Since we already established that each pair of opposite faces are equal in size, we conclude that the opposite faces would have equal area. Of the 12 edges, 4 would be length, 4 would be width and 4 would be height. The area of base of a cuboid would be length x width and that would be same as area of the top of the cuboid. The area of the front and back faces of the cuboid would be length x height each; and the area of the side faces would be width x height each. The surface area of a cuboid is thus ...
... given by the formula:
S.A. = 2*(LW + WH + HL), where L = length of the cuboid, W= width of the cuboid and H = height of the cuboid.

Consider a box of dimensions : 30cm x 40cm x 50cm, and we are asked to find the total area of cardboard required to make that box. That would be the same as finding the surface area of the box. Using the above formula, S.A. = 2*(30*40 + 40*50 + 50*30) = 9400 sqcm. That means we need 9400 square cms of card board to make that box.

Volume of a cuboid

Volume of a cuboid is the total space included inside the cuboid. Volume of a cuboid is given by the formula: V = L*W*H. For the same box mentioned above if we were to find how much cotton wool can be packed into that box, then we need to find the volume of the box. Therefore, V = 30*40*50 = 60000 cucm. So we can pack 60000 cubic cms of cotton wool into that box.

Know more about the Graphs of Exponential and Logarithmic Functions, online tutoring, Integration by Parts Rules. Online tutoring will help us to learn and do our homework very easily without going here and there.

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